5000=2000(1+(3/100))^(n)

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Solution for 5000=2000(1+(3/100))^(n) equation: 



5000=2000(1+(3/100))^(n)

We move all terms to the left:

5000-(2000(1+(3/100))^(n))=0



Domain of the equation: 100))^n)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

-(2000(1+(+3/100))^n)+5000=0

We multiply all the terms by the denominator


-(2000(1+(+3+5000*100))^n)=0



We calculate terms in parentheses: -(2000(1+(+3+5000*100))^n), so:

2000(1+(+3+5000*100))^n

We add all the numbers together, and all the variables

2000(1+500003)^n

We add all the numbers together, and all the variables

2000500004^n

Back to the equation:

-(2000500004^n)



n=0/1

n=0

Równanie nie ma rozwiązania

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